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Operator - (Subtract)operator
Subtracts two expressions
Syntax
Declare Operator - ( ByRef lhs As Integer, ByRef rhs As Integer ) As Integer
Declare Operator - ( ByRef lhs As UInteger, ByRef rhs As UInteger ) As UInteger
Declare Operator - ( ByRef lhs As Single, ByRef rhs As Single ) As Single
Declare Operator - ( ByRef lhs As Double, ByRef rhs As Double ) As Double
Declare Operator - ( ByRef lhs As T Pointer, ByRef rhs As T Pointer ) As Integer
Declare Operator - ( ByRef lhs As T Pointer, ByRef rhs As Integer ) As T Pointer
Declare Operator - ( ByRef lhs As T, ByRef rhs As T ) As Integer
Declare Operator - ( ByRef lhs As T, ByRef rhs As Integer ) As T
Parameters
| Name | Description | |
|---|---|---|
lhs | The left-hand side expression to subtract from. | |
rhs | The right-hand side expression to subtract. | |
T | Any pointer type. |
Return value
Returns the subtraction of two expressions.
Description
When the left and right-hand side expressions are numeric values,
Operator - (Subtract) returns the subtraction of the two values.If the left and right-hand side expressions are both of the
T Pointer type, for some type T, the operator performs pointer subtraction on the address, returning the result. This is different from numeric subtraction because the difference is divided by SizeOf( T ).If an integral value
n is subtracted from a T Pointer type, the operator performs pointer arithmetic on the address, returning the memory position of a T value, n indices before (assuming (-n) is within bounds of a contiguous array of T values). This behaves differently from numeric subtraction, because the Integer value is scaled by SizeOf( T ).Neither operand is modified in any way.
This operator can be overloaded to accept user-defined types.
Remarks
Usage
result = lhs - rhs
Dialect Differences
- In the -lang qb dialect, this operator cannot be overloaded.
Differences from QB
- None
See also
Example
Dim n As Single
n = 4 - 5
Print n
will produce the output:
-1
Reference
- Documented in KeyPgOpSubtract.html